In an industry the process equipment needs 5000 kg/hr of saturated steam at 10 kg/ cm2(g). For a steam velocity of 25 m/sec, what will be the diameter of the steam pipe in ‘mm’, given that the specific volume of steam at 10 kg/ cm2(g) is 0.1802 m3/kg.
CALCULATION:
Specific volume of steam at 10 kg/cm2(g) = 0.1802 m3/kg
Flow rate = 25m/sec
Mass flow rate = 5000 kg/hr
= 1.389 kg/sec
Volume flow rate = 1.389 x 0.1802
= 0.25 m3/sec
Volume flow rate is also = (π/4 x D2) x25
Therefore, (π/4 x D2) x 25 = 0.25
Hence, diameter of steam pipe line ‘D’ = [(0.25/((π/4) x 25)]0.5
= 0.1128m
or 112.8 mm
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